# Programming Praxis - Happy Numbers

Today’s problem had to do with Happy Numbers.

I split the problem up in two parts, splitting up a number up in to digits and checking whether or not the number is a Happy Number.

The first part I implemented in two different ways.

Method 1:

```
def chop(x):
r = []
length = int(ceil(log(x, 10)))
if ceil(log(x, 10)) == int(ceil(log(x, 10))):
length += 1
#a(dd), s(ubstract)
for a,s in zip(range(0, length), range(length-1, -1, -1)):
temp = x/(10**s)
for i,e in enumerate(r):
pass
temp -= e * 10**(len(r)-i)
r.append(temp)
return r
```

Method 2:

```
def chop2(x):
return [int(x) for x in str(x)]
```

Method 2 is shorter *and* faster, but I really wanted to try solving it by just using numbers.

String conversions feel a bit “dirty”.

Then finally, checking whether a number is a happy number or not:

```
def isHappyNumber(x):
if x <= 0:
return False
numbers = [x]
while x != 1:
x = sum([a**2 for a in chop(x)])
if x in numbers:
return False
numbers.append(x)
return True
```

The source can also be found on Bitbucket.